Formula: (v1 here is amp output voltage, v2 is input or dsp output & dB is known voltage gain)General formula: dB = 20 x Log (v1/v2)working backwards:voltage multiplier = antilog10 (dB/20) (NOTE - I fixed an error with the formula, my apologies... I was typing carelessly)v1 = voltage multiplier x v2
But limiting alone cannot let you power a JRX wedge with an I-Tech, can it?
Limiting is a dynamic reduction of gain you'd need some kind of static reduction in addition to appropriate limiting.
A GX7 does not have a variable gain, which I think is this static variable. An I-Tech does, correct?
Remove the itech from consideration. Let's say you want to power your JRX cab, and you've got a QSC GX3 and a PL380. Two extremes, I know. Let's say both are at 32db (the GX3 is stuck there, the PL380 can join it) and no attenuation.
If the two amps had the same gain (even if one was fixed, one set) wouldn't they have the same output? Ok... I think I know that's wrong, but I just don't understand why. It's this gain number I don't get...
How did he end up tearing up my garden en route through my bay window?
So what gain would the PL380 be at to get full power? Set that way, it would have higher output then the GX7 @ 1.2 volts input right?Thanks I realize this is taking forever, thanks!
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